What is the value of Kp?

Question

An equilibrium is established for the reaction 2 CO(g) + MoO₂(s) ⇌ 2 CO₂(g) + Mo(s). At equilibrium the partial pressure of carbon monoxide is 5.21 atm and the partial pressure of the carbon dioxide is 0.457 atm

Answer 1

Set up and ICE table:

2CO(g) + MoO₂(s) <==> 2CO₂(g) + Mo(s)

2x..............x........................0.................0.........Initial

-2x...........-x.......................+2x...............+x.........Change

5.21...................................0.457.......................Equilibrium

Actually, we didn't need to set up the ICE table since we are given the equilibrium partial pressures of the relevant speices, CO and CO2 (others are solids and do not participate in the K)

K = (PCO₂)² / (PCO)²

K = (0.457)² / (5.21)² = 0.209/27.1

K = 0.00771