Consider balanced chemical reaction when phosphorus and iodine react to produce phosphorus triodide: 2P(s)+3I2(g)------>2PI3(g)

Question

If 58.6 of I2(s) area reacted with excess P(s) to produce O . 147 mol of PI3(g),What percent yield of Pl3(g)?

Answer 1

2P(s) + 3I₂(g) ==> 2PI₃(g)

We are told that P(s) is in excess so the amount of PI₃ will depend only on the amount of I₂(s) present

moles I₂ = 58.6 g I₂ x 1 mol I₂/254 g = 0.2307 moles I₂

Theoretical yield = 0.2307 mol I₂ x 2 mol PI₃ / 3 mol I₂ = 0.154 moles PI₃

% yield = actual yield/theoretical yield (x100%) = 0.147 mol/0.154 mol (x100%) = 95.5% yield