Statistics and probability

Question

Dr. Emmett Brown has a bag of M&Ms. He has 7 green M&Ms, 12 brown M&Ms, 3 blue M&Ms, and 5 red M&Ms.

What is the probability that Emmett selects a blue M&M followed by a green M&M without replacement?

Use 4 decimals***

Answer 1

28 total M and Ms. 3 blue and 7 green.

First pick has a 3/28 probability of being blue. There are now 27 M and Ms left in the bag.

Second pick has 7/27 probability of being green.

Probability of both events occurring is 3/28 * 7/27 = 0.0278