JKL,m<j =(4x-10) m<k= (3x-7) and m<L = (4x-1) Find m<K

Question

JKL,m<j =(4x-10) m<k= (3x-7) and m<L = (4x-1) Find m<K

Answer 1

The angles of a triangle always add up to 180°. So angles J, K, and L should add up to 180°.

(4x-10) + (3x-7) + (4x-1) = 180

11x -18 = 180

11x = 198

x = 19

Since x = 19, m<K = 3(19) - 7 = 57 - 5 = 50