
Patrick B. answered 09/29/20
Math and computer tutor/teacher
X+y = 10000
0.07x + 0.06y = 610
0.07x + 0.06 ( 10000 - x) = 610
0.07x + 600 - 0.06x = 610
0.01x + 600 = 610
0.01x = 10
x = 1000
y =9000
Sophie A.
asked 09/28/20Last year, Dan had 10000 to invest. He invested some of it in an account that paid 7% simple interest per year, and he invested the rest in an account that paid 6% simple interest per year. After one year, he received a total of $610 in interest. How much did he invest in each account?
Patrick B. answered 09/29/20
Math and computer tutor/teacher
X+y = 10000
0.07x + 0.06y = 610
0.07x + 0.06 ( 10000 - x) = 610
0.07x + 600 - 0.06x = 610
0.01x + 600 = 610
0.01x = 10
x = 1000
y =9000
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