Identify the distance to the nearest 10th between S (-3,4) and T (10,-1)

Answer 1

distance square = sum of squares of the distances between the x and y coordinates

take the difference in x coordinates 10--3 = 13 and square it

take the difference in y coordinates 4--1 = 5 and square it

d^2 = (13)^2 + 5^2 = 169 + 25 = 194

d = sqr194 = almost 14 = approximately 13.8

the distance is the hypotenuse of a right triangle that has sides 13 and 5

You know it's going to be longer than 13. The hypotenuse is always longer than

either of the other 2 sides