What volume in mL of 0.3750M HCl is required to neutralize 50.00 mL of 0.8000 M NaOH?

Answer 1

HCl + NaOH ==> NaCl + H2O ... balanced equation

The mol ratio of HCl to NaOH is 1:1

moles NaOH present = 50.00 ml x 1 L/1000 ml x 0.8000 mol/L = 0.04000 moles NaOH

moles HCl needed to neutralize this = 0.0400 moles HCl (1:1 mol ratio)

Volume HCl needed: (x L)(0.3750 mol/L) = 0.04000 moles

x = 0.1067 L