
Namita S. answered 02/15/15
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Let No.of total girls =x
No. of total boys =y
x+y=629 ___________ equation 1
total children went to home=85 boys + 2/3 x girls
remaining boys are y-85
remaining girls are 1/5*(y-85)
85+ 2/3 x + y-85+ 1/5(y-85)=629
2/3 x+ y+y/5-85/5=629
2/3x+y+y/5-17=629
2/3x+y+y/5=646
LCM of denominator is 15
10x+15y+3y=9690
10x+18y=9690 _____________equation 2
y=629-x from equation 1
substitute value of y in equation 2
10x+18(629-x)=9690
10x+11322-18x=9690
-8x=-1632
x=204
so total girls are 204
girls went to home is 2/3 rd of total girls
so 204* 2/3=136
so no.of girls went to home are 136
so answer is c) 136