Given P(A) = .10, P(B) = .12, P(C) = .21, P(AC) = .05, and P(BC) = .03, solve the following

Question

Given P(A) = .10, P(B) = .12, P(C) = .21, P(AC) = .05, and P(BC) = .03, solve the following

round answers to 2 decimal places

a. P(A union C) =

b. P(B union C)

c. If A and B are mutually exclusive, P(A union B)=

Answer 1

P(A U C) = P(A) + P(C) - P(A and C) = 0.10 + 0.21 - 0.05 = 0.26

P(B U C) = P(B) + P(C) - P(B and C) = 0.12 + 0.21 - 0.03 = 0.31

If A and B are mutually exclusive then P(A and B) = 0 and

P(A U B) = P(A) + P(B) = 0.10 + 0.12 = 0.22