Point R is on line segment \overline{QS} QS ​ . Given QS=5x-2,QS=5x−2, QR=3x-6,QR=3x−6, and RS=4x-2,RS=4x−2, determine the numerical length of \overline{RS}. RS .g

Answer 1

By segment addition rule: QR + RS = QS

we are given QR = 3x-6, RS = 4x-2 and QS = 5x-2

therefore:

3x-6 + 4x - 2 = 5x - 2

7x - 8 = 5x - 2

2x - 6

x = 3

RS = 4x - 2 = 4(3) - 2 = 10