find the area of the polygon with the given vertices j(-3 4) k(4, 4) l(3 -3)

Answer 1

I don't know if you have covered determinants in your class, but if so,

Area triangle = (1/2)* abs(det x1 y1 1 where abs is absolute value and det is the determinant.

x2 y2 1

x3 y3 1)

Use x1=-3, y1 =4

x2=4, y2=4

x3=3, y3 = -3

So Area = (1/2)* abs(det -3 4 1

4 4 1

3 -3 1)

You should get Area = 49/2. Try to work out the determinant yourself to make sure you understand the process.

Again, I don't know if you have done determinants in your class. This is just one way to solve this problem. There are other ways to do it, too. Please let me know if you need additional help!

Answer 2

Sketch the co-ordinates on graph paper.

You will see that the polygon is a triangle with base 7 and altitude 7.

The area is, therefore, 24.5.

P.S. Your English grammar needs attention, too.

A sentence begins with a capital letter and ends with a period.

Also the points should properly be separated by comma.