The specific heat of a certain type of metal is 0.128 .0.128 J / (gcC) . What is the final temperature if 305 of heat is added to 68.5 g68.5 g of this metal , initially at 20.0 ?

Question

The specific heat of a certain type of metal is 0.128 .0.128 J / (gcC) . What is the final temperature if 305 of heat is added to 68.5 g68.5 g of this metal , initially at 20.0 ?

Answer 1

For this problem, we can use q = mC∆T

q = heat = 305 J (I'll assume the units are joules since you didn't include any units)

m = mass = 68.5 g

C = specific heat = 0.128 J/gº

∆T = change in temperature

Substituting and solving for ∆T we have...

305 J = (68.5 g)(0.128 J/gº)(∆T)

∆T = 34.8º

Since this is the CHANGE in temperature and since heat is ADDED, we add this to the initial temprature

Final temperature = 20.0º + 34.8º = 54.8º