A gas system has an initial temperature of 119 C with the volume unknown. When the temperature changes to 255.0 K the volume is found to be 6.37 L What was the initial volume in L?

Answer 1

Given:

T1 = 119ºC + 273 = 392K (note: always work in Kelvin (K) when working with gases)

T2 = 255.0K

V2 = 6.37 L

Asked for:

V1

Use V1/T1 = V2/T2 (Charle's Law) and solve for V1

V1 = T1V2/T2

Substitute the above values and solve