How many moles of H+ ions are present in 871 mL of 0.942 M nitric acid solution?

Question

How many moles of H⁺ ions are present in 871 mL of 0.942 M nitric acid solution?

 

______ mol H⁺

Answer 1

Nitric acid = HNO₃

HNO₃ ==> H₊ + NO₃^-

871 ml x 1 L/1000 ml = 0.871 L

Molarity = moles/L

0.871 L x 0.942 moles/L = 0.820 moles HNO3 = 0.820 moles H⁺