Solve the following, where 0° < 𝜃 < 360°, b. If sin 𝜃 = 2/3 and cos 𝜃 > 0, then find cot 𝜃.

Question

I am bad at understand trig, any help would be great :)

Answer 1

If sin and cos are both positive then angle is in first quadrant and cot = cos/sin is positive

cos^2 = 1 - sin^2

cos^2 = 1 - 4/9 = 5/9

cos = sqrt(5)/3

cot = (sqrt(5)/3) / (2/3) = sqrt(5)/2