Calculate the amount of heat required to raise the temperature of a 94 g sample of water from 31 ∘C to 66 ∘C.

Answer 1

The equation you will want to use for such problems is q = mC∆T

q = heat = ?

m = mass = 94 g

C = specific heat = 4.184 J/gº (for water; each substance has its own specific heat value)

∆T = change in temperature = 66º - 31º = 35º

q = (94 g)(4.184 J/gº)(35º) = 13,765 J = 14,000 J = 14 kJ (to 2 sig. figs.)

Answer 2