Suppose 𝑃(𝐹)=0.54; 𝑃(𝐸and𝐹)=0.2; and 𝑃(𝐸or𝐹)=0.95. Find 𝑃(𝐸

Answer 1

Assuming we are being asked for P(E),

P(F) - P(EF) = P(E'F), so P(E'F) = .54 - .2 = .34

P(E or F) - P(E'F) = P(E), so .95 - .34 = .61 = P(E)