Find a general form of an equation of the line through the point A that satisfies the given condition. A(3,-2) ; through B(-2, 4)

Answer 1

Slope of the line = (y2-y1) / (X2 -X1)= -6/5

Equation of line

y = mX +b

Plug in m = -6/5

Y = -6/5 X+b

Plug in ( 3,-2)

-2 = ( -6/5)*3 +

gives b = 8/5

So equation of line is

Y= -6/5 X +8/5

or 5Y = -6X +8