Write the equation of a line that is parallel to y=0.6x+3 and that passes through the point (-3,-5).

Answer 1

Landon:

We know the slope of y=0.6x+3 is 0.6.

To obtain line that passes through (-3,-5) and is parallel to y=0.6x+3, use

y-(-5) = 0.6*(x-(-3)). Remember the slopes of the two lines are equal.