Write an equation of the line that passes through point (6, 1) and has the slope m=−3.

Answer 1

the point slope formula for a straight line is

y-h = m(x-k)

here slope = m=-3 and a point (k,h) = (6,1), so the equation is:

y-1 =-3(x-6) or

y=-3x +18+1 =- 3x+19

3x+y=19

Answer 2

general equation of line is y=mx+b, where m is the slope and b is y-intercept and (x,y) is any point on the line. We need to find m and b to complete the equation of the line.

we are given the slope m=-3, so we just need to find b. We are given an (x,y) = (6,1) on the line, so we can substitute that x,y and m=-3 to determine b:

1 = -3(6) + b

19 = b

so equation of line is y = -3x + 19