J.R. S. answered 09/12/20
Ph.D. University Professor with 10+ years Tutoring Experience
a) NaBr
Cathode: 2H+ + 2e- ==> H2(g)
Anode: 2Br- ==> Br2 + 2e-
Overall: 2H+ + 2Br- ==> H2 + Br2
b) CuCl2
Cathode: Cu2+ + 2e- ==> Cu(s)
Anode: 2Cl- ==> Cl2 + 2e-
Overall: Cu2+ + 2Cl- ==> Cu(s) + Cl2
c) LiOH
Cathode: 2H+ + 2e-==> H2
Anode: 4OH- ==> 2H2O + O2 + 4e-
Overall: 4H+ + 4OH- ==> 2H2 + 2H2O + O2