Point R is on line segment QS. Given QS=2x+2, QR=3x-5, and RS= 5x-5, determine the numerical length of QR

Answer 1

QR + RS = QS

3x-5 + 5x-5 = 2x+2

8x-10 = 2x+2

4x-5 = x+1

3x = 6

x= 2

QR= 3x-5 = 3(2)-5 = 6-5 = 1

QR = 1

Answer 2

You draw a picture which represent your problem.

Since R is on the segment QS, the length of QS is equal to length of QR plus length of RS

QS=QR+RS

2x+2=3x-5+5x-5

Solve for x

2x+2=8x

6x=2

x=2/6=1/3

Now, use value of x to calculate QR