A(n) 84.9 kg boxer has his first match in the Canal Zone with gravitational acceleration 9.5m/s2 and his second match at the North Pole with gravitational acceleration 9.7 m/s2.

Question

A(n) 84.9 kg boxer has his first match in the Canal Zone with gravitational acceleration 9.5m/s² and his second match at the North Pole with gravitational acceleration 9.7 m/s².

What is his weight at the North Pole

Answer 1

Weight is the force exerted on a body by gravity. This force is calculated using Newton's second law of motion, which states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

In other words, Force = mass * acceleration, or F = m * a

The weight of the boxer in the canal zone is

F = 84.9 kg (the boxer's mass) * 9.5 ^m/_s² (the acceleration of gravity)

F = 806.55 N

You can find the weight at the North Pole the same way, just use 9.7 for the acceleration of gravity instead of 9.5