J.R. S. answered 09/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
rate of reaction = ∆[CH3OH]/∆t = -1/2∆[H2]/∆t = -∆[CO]/∆t
Answer A
Sarosha N.
asked 09/09/20with the rate of reaction = (Δ[CH3OH]) ÷ (Δt). If the rate of the reaction is written using the concentration of hydrogen the rate of the reaction = ___.
A) -1/2* (Δ[H2]/Δt)
B) +2* (Δ[H2]/Δt)
C) + (Δ[H2]/Δt)
D) - (Δ[H2]/Δt)
J.R. S. answered 09/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
rate of reaction = ∆[CH3OH]/∆t = -1/2∆[H2]/∆t = -∆[CO]/∆t
Answer A
The reaction stoichiometry governs the relationship of the rates as well as the mole relations between the participants in a reaction. It works even better if you assign all reactants negative stoichiometric coefficients: then you account for reactants having negative rates and products having positive rates.
rH2 ( 1 mole Methanol / -2 moles of H2) = rMethanol
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