a rectangular garden has a length that is 3 times its width. the perimeter is 66 feet. what are the dimensions of the garden

Answer 1

Perimeter is equal to all four sides added together.

Length = 3W; L=3W

So

P = 2(W) + 2(L) substitute the equation for length above you get

P = 2(W) + 2(3W) and combine

P = 2W + 6W = 8W; put in what the perimeter is and solve for W

66 = 8W, so W = 8.25

W = 8.25, L = 24.75

Answer 2

w = width of garden

3w = length of garden

perimeter = 2*width + 2*length = 66

2*w + 2 * 3w = 66

8w = 66

w = 8.25 feet

length = 3w = 24.75 feet

Answer 3

l = length (3x ), w = width (x)

perimeter = 2l + 2w

p = 2(3x) + 2(x)

66 = 6x + 2x

66 = 8x

x = 8.25, width

3x = 24.75, length

check

66 = 2(24.75) + 2(8.25)

66 = 49.5 + 16.5

66 = 66

hope it helps Dennis