Find the distance between A(3, 3) and B(-2, -6) to the nearest hundredth.

Answer 1

Use the distance formula

d^2 = sum of squares of the difference in y coordinates plus difference in x coordinates

d^2 = (3 - - 2)^2 + (3--6)^2 = 5^2 + 9^2 = 25 + 81 = 106

d = sqr 106 = 10.29