Please read the description as this is a long question.

Question

Pb(OH)Cl, one of the lead compounds used in ancient Egyptian cosmetics, was prepared from PbO according to the following ancient recipe:

PbO + NaCl + H₂O -> Pb(OH)Cl + NaOH

part 1-

How many grams of PbO and how many grams of NaCl would be required to produce 10.0 g of Pb(OH)Cl?

Mass of PbO required = ? g

Part 2-

Mass of NaCl required = ? g

Answer 1

PbO + NaCl + H₂O -> Pb(OH)Cl + NaOH ... balanced equation

(1). From the balanced equation we see that 1 mole Pb(OH)Cl requires 1 mole PbO.

molar mass Pb(OH)Cl = 259.7 g/mol

moles Pb(OH)Cl in 10.0 g = 10.0 g x 1 mol/259.7 g = 0.0385 moles

moles PbO needed = 0.0385 mol Pb(OH)Cl x 1 mol PbO/mol Pb(OH)Cl = 0.0385 mol PbO needed

mass of PbO needed = 0.0385 mol PbO x 223.2 g/mol = 8.59 g PbO needed

(2). From the balanced equation we see that 1mol PbO reacts with 1 mol NaCl, so it will require 0.0385 moles of NaCl.

mass of NaCl needed = 0.0385 mol NaCl x 58.4 g/mol = 2.25 g NaCl needed