stichiometry reaction

Question

How many moles of methane (CH₄) are required to react completely with 89.5 L of carbon tetrachloride according to the following reaction at 0°C and 1 atm?

methane (CH₄) (g) + carbon tetrachloride(g)dichloromethane (CH₂Cl₂) (g)

Answer 1

CH₄ + CCl₄ ==> 2CH₂Cl₂ ... balanced equation

0ºC and 1 atm = STP and at STP 1 mol of gas = 22.4 L

89.5 L CCl₄(g) x 1 mol/22.4 L = 3.995 moles CCl₄

moles CH₄ = 3.995 mol CCl₄ x 1 mol CH₄/1 mol CCl₄ = 3.995 mol CH₄ = 3.40 moles CH₄ (3 sig.figs.)