J.R. S. answered 08/20/20
Ph.D. University Professor with 10+ years Tutoring Experience
First part, there isn't enough information provided. No results of the reaction are given.
Second part, you have the balance equation 2Al + 6H2SO4 ==> Al2(SO4)3 + 3SO2 + 6H2O
To find L of SO2 produced, we first want to find the moles of SO2 and then use the Ideal Gas Law to find L.
The SO2 derives from the H2SO4, so we can work with that alone.
50 ml H2SO4 x 1.65 g/ml = 82.5 g H2SO4 but since it is only 73.8% pure, that equates to 60.9 g H2SO4
moles H2SO4 = 60.9 g H2SO4 x 1 mol/98 g = 0.621 moles H2SO4
moles SO2: 0.621 mol H2SO4 x 3 mol SO2/6 mol H2SO4 = 0.31 mol SO2
Using PV = nRT and solving for V, we have...
V = nRT/P = (0.31 mol)(0.0831 Lbar/Kmol)(298K)/1.005 bar
V = 7.65 L SO2