Tom K. answered 08/20/20
P(E1) = 11/36 (P(6 on first die) + P(6 on second die) - P(6 on both die))
P(E2) = 10/36 = 5/18 (P(5 on first die and no 5 on second die) + P(5 on second die and no 5 on first die))
P(E3) = 1/6 (P(1 on both dice) + P(2 on both dice) + P(3 on both dice) + P(4 on both dice) + P(5 on both dice) + P(6 on both dice))
i) P(E1E2) = 1/18 (P(5 on first die and 6 on second die) + P(6 on first die and 5 on first die))
P(E1) * P(E2) = 11/36 * 5/18 = 55/648 is not equal to 1/18 not independent
ii) P(E2E3) = 0 (if 5 on only one die, not possible to have same number on both dice) P(E2) * P(E3) = 5/18 * 1/6 = 5/108 is not equal to 0 not independent
iii) P(E1E3) = 1/36 (P(6 on both dice)) P(E1) * P(E3) = 11/36 * 1/6 = 11/216 is not equal to 1/36 not independent