how do you find the missing endpoint if B is the midpoint of AC? A (1,7) B (-3,1)

Answer 1

A= (x₁, y₁) B (mid point ) = (x₂, y₂) c= (x_3,y₃₎

x_{1= 1} x_{2= -3}

y₁= 7 y₂= 1

X₂ = (X₁+ X₃) / 2

then plug in the numbers

-3 = (1+x₃) / 2 multipy both side by 2

(-3) (2) = (1+ x₃) /2 (2)

-6= 1+x_{3 subtract 1 both sides}

-6-1 = 1-1 + x₃

_{-7 =} x₃

Y₂₌ (Y₁+Y₃) / 2 then plug in the numbers

1= (7+ Y₃) / 2 multipy both side by 2

(1) (2)= (7+ Y₃) / 2 (2)

2= 7+Y_{3 subtract 7 both sides}

2-7 = 7 -7+ Y₃

-5= Y₃

the other end point is c = (-7, -5)

Answer 2

A = (1,7)

B = (-3,1)

C = (?,?)

Considering A and C are endpoints, and B is their midpoint, C is the same distance from B as B is from A.

In the X direction, B is -4 spots away from A (-3-1 = -4)

In the Y direction, B is -6 spots away from A (1-7 = -6)

Therefore, C is -4 away from B in the X direction and -6 spots away in the Y direction.

B = (-3,1)

C = (-3-4,1-6) = (-7,-5)