By the segment addition rule, length of ST + length TU equals length of SU so
3x -1 + 3x = 4x + 1
6x - 1 = 4x + 1
2x = 2
x = 1
substituting value of x back into formula for length of SU: 4(1) + 1 = 5
Nancy L.
asked 08/14/20By the segment addition rule, length of ST + length TU equals length of SU so
3x -1 + 3x = 4x + 1
6x - 1 = 4x + 1
2x = 2
x = 1
substituting value of x back into formula for length of SU: 4(1) + 1 = 5
Since T is on segment SU we know the whole is eqaul to the sum of it’s parts.
ST + TU = SU substitute
3x - 1 + 3x = 4x + 1 simplify
6x - 1 = 4x + 1 solve for x
2x = 2
x = 1
ST = 3(1) -1 = 2
TU = 3(1) = 3
SU = 4(1) + 1 = 5
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