Amayas O.
asked 08/01/20find the following .. cot2x
Let cos x = 7/8 with A in QIII and find the following.
cot 2x
1 Expert Answer

Jon S. answered 08/01/20
Patient and Knowledgeable Math and English Tutor
cos x = 7/8
sin x = sqrt(1 - cos^2x) = sqrt(1 - 49/64) = sqrt(15/64) = sqrt(15)/8
tan x = sinx/cosx = sqrt(15)/7
tan2x = (2 * tanx) / (1 - tan^2x) = (2 *sqrt(15)/7)/(1 - 15/49) = (2*sqrt(15)/7)/(34/49)= (2*sqrt(15)/7)(49/34) =
(7 * sqrt(15))/17
cot2x = 1/tan2x = 17/(7 * sqrt(15)) = 17*sqrt(15)/105
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Tom K.
cos is negative in QIII08/01/20