Since this is a left-tailed test and the level of significance is 0.02, the critical z value is the z-value for which P(Z < z) = 0.02, which is -2.054.
So reject null hypothesis is sample z statistic < -2.054
The population proportion (p) is 0.42
The sample proportion (phat) = 55/139 = 0.396
The sample size (n) = 139
The sample z-statistic = (phat - p)/(p*(1-p)/n)**0.5
The sample z-statistic = (0.396-0.42)/(0.42*0.58/139)**0.5 = -0.573
The sample z-statistic is not in the critical region, so do not reject null hypothesis.
There is not sufficient sample evidence to support the claim that the population proportion is less than 0.42.