For this situation you can utilize the z-statistic (standardized normal distribution).
z statistic = (sample mean - population mean)/(population standard deviation/sample size**0.5), where sample size = 58, sample mean =58.2, population mean = 56.8, population standard deviation = 10.8
The p-value is P(Z > z-statistic). It is compare to alpha = 0.005. If the p-value is less than 0.005, then the null hypothesis is rejected, otherwise it is not rejected.
If the null hypothesis is rejected, then the sample data support the claim that the population mean is greater than 56.8, otherwise, there is not sufficient sample evidence to support the claim that the population mean is greater than 56.8.