Patrick B. answered 07/29/20
Math and computer tutor/teacher
Angle A in quadrant3:
y=opposite = 21 and x=adjacent=20
then hypotenuse = sqrt( 21^2 + 20^2)
= sqrt( 441 + 400)
= sqrt( 881)
So then sin A = 21/sqrt(881) = 21 * sqrt(881)/881
and cos A = 20/sqrt(881) = 20*sqrt(881) / 881
Angle B in Quadrant 2:
adjacent = -5 and hypotenuse = 13
then by pythagorean, y=opposie = 12
so then sin B = 12/13, cos B = -5/13 as given,
and tan B = -13/12
sin (A+B) = sin A cos B + cos A sin B
= 21 * sqrt(881)/881 * (-5/13) + 20*sqrt(881)/881 * (12/13)
= (-105/(13*881)) * sqrt(881) + (20/ (13*881))*sqrt(881)
= -85/(13*881) * sqrt(881)