Answer: ??? °C.

Question

A sample of solid iodine is heated with an electrical coil. If 57.6 Joules of energy are added to a 10.8 gram sample initially at 23.3°C, what is the final temperature of the iodine?

Answer 1

One needs to know the specific heat of solid iodine. Looking it up I find it to be 0.427 J/g/ºC

You can then use the formula q = mC∆T where...

q = heat = 57.6 J

m = mass = 10.8 g

C = specific heat = 0.427 J/g/ºC

∆T = change in temperature

Solve for ∆T and add that to 23.3ºC to get the final temperature of the iodine. Make sense?