write an equation for a circle that has a center at (-6,5) and passes through the point (-11,3)

Answer 1

Jessie

A circle center (a,b), radius r has equation (x-a)²+ (y-b)²=r²

So as the center is (-6,5) a = -6 and b = 5

And the radius squared will be the distance squared between the center and the given point. To find this you take the difference in x values (squared) and add to the difference in y values (squared).

In other words 5 squared + 2 squared = 25 + 4 = 29

So a= -6, b =5, r²=29 so your equation is (x+6)²+(y-5)²=29

If required you can multiply out the two squared brackets and simplify the expression (exercise for you).

Mike

Answer 2

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