
William W. answered 07/21/20
Experienced Tutor and Retired Engineer
This seems to be a little ambiguous but I'm guessing it's like this:
where we are measuring off the trampoline's relaxed surface position. We can use the equation:
h(t) = Acos(B(t - C)) + D
where:
A is the Amplitude, in this case that would be 200 cm from the relaxed position plus the 2 cm initial deflection or 202.
B is derived from the period and is in fact (2π)/period = (2π)/10 = π/5
C is the time shift and is 6
and D is the vertical shift which in this case is -2
So: h(t) = 202cos(π/5(t - 6)) - 2