AgNO3+NaCl= AgCl+NaNO3 AgCl is precipitation, it does not dissolve in water
Let's find M AgNO3=170 NaCl=58.5 AgCl=143.5
50mL 12% solution of AgNO3 means 6 g of powder dissolved in 50 mL solution.
( 12% solution means - 12 gram of AgNO3 in 100 mL solution)
50 mL 6.7% NaCl contents 3.35 gram of salt NaCl
So, 6 g of AgNO3 mixed with 3.35 gram of NaCl. Let's find out if this is a right proportion.
look on their molar mass: 170 g AgNO3 will react with 58,5 g NaCl
As we can see that 3.35 g NaCl is too much to react with 6 g AgNO3.
We can find right mass of NaCl: (6 x 58.5) :170= 2.06 g
Since, 2.06 g is right number now, we can find precipitation AgCl
(2.06 x 143.5): 58.5= 5.05 gram of precipitation AgCl