How many moles of ammonium ions are in 10.0g of ammonium phosphate

Answer 1

(NH₄)₃PO₄ is the formula for ammonium phosphate

Molar mass of ammonium phosphate = 149.1 g/mol

moles ammonium phosphate in 10.0 g = 10.0 g x 1 mol/140.1 g = 0.0671 moles (NH₄)₃PO₄

moles NH₄⁺ ions = 0.0671 moles (NH₄)₃PO₄ x 3 mol NH₄⁺/mol (NH₄)₃PO₄ = 0.2013 mol NH₄⁺ ions

(Note: there are 3 moles of NH4+ for each mol of (NH4)3PO4)

Rounding to 3 significant figures, you have 0.201 moles of ammonium (NH₄⁺) ions.

Answer 2

(NH3)3PO4 this is Ammonium Phosphate

When dissolve and dissociate It has 3 ions of Ammonium

1. Let's find M of Ammonium Phosphate, 146g
2. 146g contain 51 g of ammonium or 1 mol
3. but 10 g have 3.49 g or 0.068 mol