sin^2=2-2cos x Find all solutions of the equation in the interval [0,2pi).

Answer 1

1 - cos²x = 2 - 2cosx, or cos²x - 2cosx + 1 = 0, (cosx - 1)² = 0, cosx = 1, x = 0

Answer: x = 0 only solution of this equation on interval [0, 2π)