Jackson H. answered 07/15/20
Mechanical Engineer | Certified EIT and CSWA
90deg - 30deg = 60 degrees
cos(60) = 1/2
sin(60) = sqrt(3) / 2
30 * 1/2 = 15
30 * sqrt(3) / 2 = 15 sqrt(3)
B if its the vector is pointing towards quadrant 1
Max C.
asked 07/15/20If a force of 30 pounds is directed 30° from the vertical, what vector represents this force?
A.)-15i-15√3j
B.)15i+15√3j
C.)-15i+15√3j
D.)15i-15√3j
Jackson H. answered 07/15/20
Mechanical Engineer | Certified EIT and CSWA
90deg - 30deg = 60 degrees
cos(60) = 1/2
sin(60) = sqrt(3) / 2
30 * 1/2 = 15
30 * sqrt(3) / 2 = 15 sqrt(3)
B if its the vector is pointing towards quadrant 1
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