Write an equation that is perpendicular to y=-2x+4 and passes through the point (-2,0)

Answer 1

Need an equation for the line perpendicular to

y = -2x + 4

m = -2

Slope of the equation for the perpendicular line would be the negtive inverse of -2 or

m = 1/2

Equation of the Perpendicular line

y = 1/2(x) + b

Since this passes through (-2, 0)

0 = 1/2(-2) + b

0 = -1 + b

1 = b

So the equation for the perpendicular line is

y = 1/2(x) + 1

You can check by graphing both lines at Desmos.com

Answer 2

y=(1/2)x + 1

In the original equation the slope is -2. The slope of a line perpendicular to that will be positive 1/2. Plug 1/2 as the slope and the new point (-2,0) into point slope form and you get

y-(0)=(1/2)(x-(-2))

Simplify to get

y=(1/2)(x+2)

Simplify once more to get

y=(1/2)x + 1