sample size (n) = 112
population mean = 51.2
population standard deviation 12.5
x = value, want to find P(51.1 < x < 51.8)
x is non-standard normally distributed N(51.2,12.5)
convert x = 51.1 and 51.8 to standard normally distributed N(0,1) via equation z = (x - population mean)/population standard deviation. z is N(0,1).
convert x = 51.1: (51.1-51.2)/12.5 = -0.008
convert x = 51.8: (51.8-51.2)/12.5 = 0.048
P(51.1 < x < 51.8) --> P(-0.008 < z < 0.048) = 0.0239