The margin of error is z-critical for 95% CI * sqrt[p*(1-p)/n], where z-critical = 1.96, p = 0.47 and n=1026
The CI = 0.47 +/- the margin of error
Eric C.
asked 07/11/20A survey of 1,026 people asked: “What would you do with an unexpected tax refund?” Forty-seven percent responded that they would pay off debts.
a. At 95% confidence what is the margin of error?
b. Construct the 95% confidence interval for the population proportion of people who would pay off debts with an unexpected tax refund.
The margin of error is z-critical for 95% CI * sqrt[p*(1-p)/n], where z-critical = 1.96, p = 0.47 and n=1026
The CI = 0.47 +/- the margin of error
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