
Amanda G. answered 07/14/20
Patient High School Biology and Elementary Math/Science Tutor
Hi Rebecca,
This is a great question. Questions like this can be a bit difficult because they often change up the names of the variables we are used to working with. The key to working out a problem like this is to notice that q=x and p=y. However, let's still work this problem out in terms of q and p.
we have two sets of data.
(q1,p1)=(125,3.50)
and
(q2, p2)=(350,2.00)
At this point you may realize that both data sets look a whole lot like coordinates. This is a good!!!
Because if they are coordinates than we can use the equation y=mx+b or in this case p=mq+b
Next, we need to remember the definition of slope:
m=rise/run ----> (p2-p1)/(q2-q1)
So, for this problem our slope would be:
m=(2.00-3.50)/(350-125)= -1.5/225 ----> -1/150
Now all we are missing in our equation is b.:
p=(-1/150)q+b
To find b we chose one of our two coordinates and subtract the q of the coordinate from the q of our equation and the p of our coordinate from the p of our equation.
p-3.50=(-1/150)(q-125)
distribute -1/150 to the x and 125
p-3.50=-1/150(q)+(5/6)
add 3.50 to both sides
p= -1/150(q)+13/3
Now, all you need to do is rearrange the equation in terms of q=? which I will let you try first. Let me know if you get stuck on this step and I will walk you through it.
You should check to make sure your equation is correct by plugging one of your coordinate's p's in for p and solving. It should equal the q of that same coordinate.
To solve the final question plug 1.50 in for p and solve for q
Please let me know if you have any questions or need help with anymore problems,
-Amanda G.