Ezra V.

asked • 07/10/20

An object is launched directly upward from 384 feet above the ground

an object is launched directly upward from 384 feet above the ground. The height, h (in feet), of the object t seconds after being launched is given by the formula, h=16t^2 + 32t + 384. How long will it take the object to hit the ground.

Joel L.

tutor
Are you sure that the coefficient of t^2 is 16 and not -16? That equation will never hit the ground because basically, the graph of that quadratic is open up and has no x-intercept.
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07/11/20

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