
William W. answered 07/11/20
Top Algebra Tutor
To find the systolic pressure for a person of age 45 years, just plug in y = 45:
P = 0.004y2 - 0.02y + 120
P = 0.004(45)2 - 0.02(45) + 120
P = 0.004(2025) - 0.9 + 120
P = 8.1 - 0.9 + 120
P = 127.2
To find a person's age if their systolic pressure is 127.54 mm Hg, plug in P = 127.54
P = 0.004y2 - 0.02y + 120
127.54 = 0.004y2 - 0.02y + 120
0 = 0.004y2 - 0.02y - 7.54
Use the quadratic formula to solve this. The quadratic formula (for ay2 + by + c = 0) is:
y = [-b ± √(b2 - 4ac)]/(2a)
In this case a = 0.004, b = - 0.02 and c = - 7.54 so:
y = [-b ± √(b2 - 4ac)]/(2a)
y = [-(-0.02) ± √((0.02)2 - 4(0.004)(-7.54))]/(2(0.004))
y = [0.02 ± √(0.0004 + 0.12064)]/0.008
y = [0.02 ± √0.12104]/0.008
y = [0.02 ± 0.3479]/0.008
So, breaking it into 2 parts
1) y = [0.02 + 0.3479]/0.008 or y = 0.3679/0.008 = 45.989
2) y = [0.02 - 0.3479]/0.008 or y = -0.3279/0.008 = -40.989
Since -40.988 makes no sense (40.989 years before birth), we throw that answer out.
The age where a person's systolic pressure is 127.54 mm Hg is 46 (rounded)