Mean = 7.6 hours, std deviation = 0.67 hours
x = hours sleep
want to find P(x > 8.9)
convert x = 8.9 from N(7.6, 0.67) to standard normal N(0,1) via transformation:
Z = (x - mean)/std = (8.9 - 7.6)/0.67 = 1.94
P(x > 8.9) --> P(z > 1.94) = P(z < -1.94) = 0.0262